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agscientific(优势品牌)
主营:嘌呤霉素,G-418,酶抑制剂,基因选择,抗生素和蛋白质纯化试剂
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当前位置: 首页 > 产品中心 > Stimulus > AG Scientific/E-64/E-2030/25毫克
商品详细AG Scientific/E-64/E-2030/25毫克
AG Scientific/E-64/E-2030/25毫克
AG Scientific/E-64/E-2030/25毫克
商品编号: E-2030-25mg
品牌: agscientific
市场价: ¥4100.40
美元价: 3075.30
产地: 美国(厂家直采)
公司:
产品分类: 刺激/抑制试剂
公司分类: Stimulus
联系Q Q: 3392242852
电话号码: 4000-520-616
电子邮箱: info@ebiomall.com
商品介绍

E-64isanIrreversIBLe,potentandhighlyselectiveinhibitorofcysteineproteases.Doesnotaffectcysteineresiduesinotherenzymes.Actsbyformingathioetherbondwiththioloftheactivecysteine.E-64willnotinhibitserineproteases(excepttrypsin),butinhibitsactivation-inducedprogrammedcelldeathandrestoresdefectiveimmuneresponsesinHIV.Specificactivesitetitrant.

E-64inhibitscalpain,papain,andcathepsinB,cathepsinL.ThecompoundhasbeenreportedtoinhibitintracellularBaxproteaseactivity,andreduceoxidativestress,whichincludesadecreaseinMDAlevels,ICAM-1expressionandMOPactivity.E-64hasalsobeenusedtostudyexcystationinGiardialamblia.

E-64reducesinflammationincysticfibrosispatients.E-64playsarolein stABIlizingtheCytoskeletonproteinSynaptopodin(Synpo),aswellas,steadyingsignaltransducerandactivatoroftranscription-3(STAT3).StudiessuggestthepotentialuseofSTAT3inhibitorsintherapyofglomerulardiseases.

 

 

AdditionalInformation

AdditionalInformation

SynonymsL-trans-Epoxysuccinyl-Leu-4-guanidinobutylamide,L-trans-Epoxysuccinyl-Leu-agmatine
Product#E-2030
CAS#66701-25-5
ChemicalNametrans-Epoxysucciny-L-leucyl-amido(4-guanidino)butane;(L-3-trans-Carboxyoxiran-2-Carbonyl)-L-Leucyl-Admat
FormulaC15H27N5O5.0.5H2O
MW357.4
AppearanceWhiteSolid
Purity≥99%byHPLC
Solubility15mg/mlin1:1mixturewater/ethanol
StorageTemp-20°C
品牌介绍
AG Scientific, Inc.成立于1997年,专注于创新生化制剂以及用于诊断测试开发的定制原材料,以推进临床前研究药物开发。产品涉及抗生素,生物洗涤剂,缓冲液,诊断,酶,医疗设备试剂,蛋白酶K,还原剂,RNase A等。
MDLNumberMFCD00080261
ChemACXX1036521-8
InChIInChI=1S/C15H27N5O5/c1-8(2)7-9(20-13(22)10-11(25-10)14(23)24)12(21)18-5-3-4-6-19-15(16)17/h8-11H,3-7H2,1-2H3,(H,18,21)(H,20,22)(H,23,24)(H4,16,17,19)/t9-,10-,11-/m0/s1
SMILESCC(C)C[C@@H](C(=O)NCCCCNC(=N)N)NC(=O)[C@@H]1[C@H](O1)C(=O)O